Page 21 - MATINF Nr. 9-10
P. 21

A generalization of Mollweide’s formula, rather Newton’s                                       21



                Anticipating reducing the formula (3) to (1), rename elements of the figure as in Figure 2:

                                                                                    0
                                                                         0
                That is, angles α and γ have been sub-divided into α + α and γ + γ , and the segment labels
            have been scrambled: a = |BC|, b = |AD|, c = |AB|, d = |CD|. Note that δ = π − β (as β and
            δ are inscribed angles subtending opposing arcs). With these changes, the formula in question
            becomes
                                                                                    0
                                                    1
                                                            0
                                                                            1
                              c + d     1        sin (α + α + β)         sin (α + α + β)
                                    cot θ =         2                 =     2             .               (4)
                                                                            1
                                                  1
                                                                                    0
                                                         0
                              a + b     2     cos (γ + γ − (π − β))      sin (γ + γ + β)
                                                  2                         2
                If we slide vertex D along the circle to coincide with C (so that E does as well), we find
                                                0
                   0
            that α and d shrink to nothing; γ and θ adjust to match β and γ, respectively; and β and δ
            don’t change at all (see Figure 3).





















                                                                 0
                                                                                   0
                                Figure 3: If C = D = E, then α = 0, γ = θ and γ = β.

                So, (4) becomes

                                                       1
                                                                            1
                                   c + 0      1     sin (α + 0 + β)     sin (α + β)
                                                                            2
                                                       2
                                          cot γ =                    =               .                    (5)
                                                       1
                                                                           1
                                   a + b      2     sin (γ + β + β)     sin (γ + 2β)
                                                       2                   2
                Since α + β + γ = π, we have
                                     α + β = π − γ,           γ + 2β = π − (α − β)

            whence (5) becomes

                                             1
                                                                                 1
                                                                1
                                    c     cos γ        sin  π  − γ           cos γ
                                        ·    2   =         2    2      =         2
                                             1
                                                             1
                                                                              1
                                  a + b sin γ       sin  π  − (α − β)     cos (α − β)
                                             2          2    2                2
            and we can write
                                                              1
                                                  a + b   cos (α − β)
                                                        =     2        ,
                                                                 1
                                                    c         sin γ
                                                                 2
            which is Newton’s formula.
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