Page 104 - MATINF Nr. 13-14
P. 104

104                                                                                M.N. Popescu



            deci
                                                                    2
                                                        1
                                             0
                      card F n + card D n = C · D n + C · D n−1 + C · D n−2 + . . . + C n−2  · D 2 + 1.
                                             n         n            n                 n
            Cum S n = D n ∪ F n , D n ∩ F n = Ø s , i card S n = n!, obt , inem c˘a
                                                1
                                     0
                                                            2
                                                                              n−2
                              n! = C · D n + C · D n−1 + C · D n−2 + . . . + C n  · D 2 + 1.
                                     n
                                               n
                                                            n
            Cum D 1 = 0, notˆand D 0 = 1, relat , ia anterioar˘ devine
                                                            a
                                                   2
                            0
                                      1
                                                                                              n
                    n! = C · D n + C · D n−1 + C · D n−2 + . . . + C n n−2  · D 2 + C n n−1  · D 1 + C · D 0 .
                                                  n
                                      n
                                                                                              n
                           n
                       k
            Folosind C = C   n−k , rescriem relat , ia anterioar˘ sub forma
                                                            a
                             n
                       n
                                                           n
                                                          X
                                                                k
                                                    n ! =     C D k .
                                                               n
                                                          k=0
                Folosim punctul 5.d pentru u k = k!, v k = D k s , i obt , inem
                      n                    n                                 n       n−k       n       k
                    X        n−k  k       X        n−k     n!               X   (−1)          X   (−1)
              D n =     (−1)     C · k! =     (−1)                 · k! = n!             = n!           .
                                  n
                                                       k! · (n − k)!            (n − k)!            k!
                     k=0                  k=0                               k=0               k=0
                7. a. Probabilitatea uniform˘a pe D n este
                                                       card (A)
                                             P (A) =            , ∀A ⊂ D n .
                                                       card (D n )
            Din punctele 4 s , i 6 avem
                                                                                      n−1
                       card {σ ∈ D n : ε (σ) = 1} − card {σ ∈ D n : ε (σ) = −1} = (−1)    (n − 1) ,
                                                                                       n       k
                                                                                      X   (−1)
                        card {σ ∈ D n : ε (σ) = 1} + card {σ ∈ D n : ε (σ) = −1} = n!           ,
                                                                                            k!
                                                                                      k=0
            din care obt , inem
                                                          "                       n       k  #
                                                        1       n−1              X   (−1)
                           card {σ ∈ D n : ε (σ) = 1} =    (−1)     (n − 1) + n!             ,
                                                        2                              k!
                                                                                 k=0
                                                          "                         n        #
                                                        1         n−1              X   (−1) k
                         card {σ ∈ D n : ε (σ) = −1} =     −(−1)      (n − 1) + n!             .
                                                        2                                k!
                                                                                   k=0
            Prin urmare

                                                                         n
                                                                         P  (−1) k      n−1
                                                                     n!          − (−1)     (n − 1)
                                   card {σ ∈ D n : ε (σ) = −1}    1     k=0  k!
                   P (Y n = −1) =                              =    ·                               ,
                                                                                   n
                                            card (D n )           2               P  (−1) k
                                                                               n!
                                                                                       k!
                                                                                  k=0
                                                                       n
                                                                       P  (−1) k       n−1
                                                                    n!         + (−1)     (n − 1)
                                   card {σ ∈ D n : ε (σ) = 1}   1           k!
                     P (Y n = 1) =                           =    ·   k=0                         .
                                                                                 n
                                           card (D n )          2               P   (−1) k
                                                                             n!
                                                                                     k!
                                                                                k=0
   99   100   101   102   103   104   105   106   107   108   109