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A dynamic identity in a triangle and some applications




            Thanos Kalogerakis       1




                                                               Theorem 1. Consider a triangle ABC and
                                                               P any point on its circumcircle except A, B, C
                                                               (see Figure 1).

                                                                            0
                                                                         0
                                                                       0
                                                                   If a , b , c are the distances of P to the
                                                               sidelines of ABC, then the following identity
                                                               is true:
                                                                    a    b    c            ®  a  b  c  ´
                                                                       +    +    = 2 · max    ,   ,     .
                                                                    a 0  b 0  c 0           a 0  b 0  c 0





                               Figure 1

            Solution: Since C 1 B 1 A 1 is the Simson line of ABC wrt to P, we have, from areas equality,



                                                                                     0 0
                                                              0 0
                                                                          0 0
                                                          ⇔ a c sin B = b c sin A + a b sin C ⇔
                                                                                            “
                                                                                “
                                                                    “
                         2A PC 1 A 1  = 2A PC 1 B 1  + 2A PB 1 A 1
                                              sin B    sin A   sin C sines low
                                                                   “
                                                  “
                                                          “
                                                    =        +         ⇔
                                                b 0     a 0      c 0
                                b       a       c      b    a    c    a    b    c      b
                                   =        +      ⇔     =    +    ⇔     +    +    = 2   ⇔
                              2Rb 0   2Ra 0   2Rc 0   b 0   a 0  c 0  a 0  b 0  c 0   b 0

                                           a    b    c           ®  a  b   c  ´
                                             +    +    = 2 · max     ,   ,    .                           (1)
                                           a 0  b 0  c 0           a 0  b 0  c 0



                                                       b    a     c
            Remark 1. We can keep the easiest form,       =    +   , considering P lying on minor arc AC
                                                       b 0  a 0  c 0
                       a     b    c                                           c     a    b
            or cyclic,    =    +    , with P lying on minor arc BC and          =     +   , with P lying on
                       a 0   b 0  c 0                                         c 0  a 0   b 0
            minor arc AB.



               1
                Mechanical Engineer, National Technical University of Athens, Kiato, Korinthia, Greece, kalogerakis@hol.gr

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